刘宸志 CEUA • 2年前
using namespace std;
int main(){
int n,a[200005],sum=1;
cin>>n;
for(int i=1;i<=n;i++)
cin>>a[i];
sort(a+1,a+n+1);
for(int i=2;i<=n+1;i++){
if(a[i]==a[i-1])
sum++;
else{
cout<<a[i-1]<<' '<<sum<<endl;
sum=1;
}
}
return 0;
}
评论:
using namespace std;
int main() {
int a[10010],ci,n;
cin>>n;
for(int i=1;i<=n;i++)
cin>>a[i];
sort(a+1,a+n+1);
cout<<a[n/2+1];
return 0;
}
using namespace std; int a[10010];
int main() {
int n, x;
cin >> n;
for (int i = 0; i < n; i++)
cin >> a[i];
cin >> x;
for (int i = 0; i < n; i++) {
if (a[i] >= x) {
cout << x << " ";
x = 999999999;
}
cout << a[i] << " ";
}
if (x != 999999999)
cout << x;
return 0;
}
using namespace std;
int n, m, atime[2][20][20], ans[2][100000], ans_num[2];
void func(int people, int locate, int cost) {
if (locate == n) {
ans[people][ans_num[people]] = cost;
ans_num[people]++;
return ;
}
for (int i = locate + 1; i <= n; i++) {
if (atime[people][locate][i]) {
func(people, i, cost + atime[people][locate][i]);
}
}
}
int main() {
cin >> n >> m;
for (int i = 0; i < m; i++) {
int a, b, c, d;
cin >> a >> b >> c >> d;
atime[0][a][b] = atime[0][b][a] = c;
atime[1][a][b] = atime[1][b][a] = d;
}
func(0, 1, 0);
func(1, 1, 0);
sort(ans[0], ans[0] + ans_num[0]);
sort(ans[1], ans[1] + ans_num[1]);
for (int i = 0; i < ans_num[0]; i++) {
for (int j = 0; j < ans_num[1]; j++) {
if (ans[0][i] == ans[1][j]) {
cout << ans[0][i] << endl;
return 0;
}
}
}
cout << "IMPOSSIBLE" << endl;
return 0;
}
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