hf99 • 2天前
using namespace std; int main() {
int n;
cin >> n;
long long sum = 1;
if (n % 2 == 0)
{
for (int i = 2; i <= n; i = i + 2)
{
sum = sum * i % 100000;
}
}
else
{
for (int i = 1; i <= n; i = i + 2)
{
sum = sum * i % 100000;
}
}
cout << sum;
return 0;
}
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