周睿 • 13小时前
using namespace std; int a[105] [55];
int main() {
int n, m;
cin >> n >> m;
int ans = 0;
for (int i = 1; i <= n * 2; i++ )
for (int j = 1; j <= m; j++ )
cin >> a[i][j];
for (int i = 1; i <= n; i++ ) {
for (int j = 1; j <= m; j++ )
if (a[i][j] == a[n + i][j])
ans++;
}
cout << ans;
return 0;
}
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