左一酱(HX) • 11小时前
using namespace std;
int main() {
int a[10][10];
int n, m;
for (int i = 1; i <= 5; i++)
for (int j = 1; j <= 5; j++)
cin >> a[i][j];
cin >> n >> m;
for (int i = 1; i <= 5; i++) {
int t = a[n][i];
a[n][i] = a[m][i];
a[m][i] = t;
}
for (int i = 1; i <= 5; i++) {
for (int j = 1; j <= 5; j++)
cout << a[i][j] << " ";
cout << endl;
}
return 0;
}
评论:
请先登录,才能进行评论