LZT • 6个月前
using namespace std;
int main() {
long long m, k, x;
cin >> m >> k >> x;
int n = 0;
if (m < 0) {
m = 0 - m;
}
for (; m > 0; m /= 10) {
if (m % 10 == x) {
n++;
}
}
if (n == k) {
cout << "YES";
} else {
cout << "NO";
}
return 0;
}
评论:
using namespace std;
int main() {
long long k, c;
long long num = 0, b ;
cin >> k >> c >> b;
if (k < 0) {
k *= -1;
}
while (k > 0) {
if (k % 10 == b) {
num++;
}
k /= 10;
}
if (num == c) {
cout << "YES";
} else {
cout << "NO";
}
return 0;
}
请先登录,才能进行评论