LZT • 18天前
using namespace std;
int main() {
int n; double m, a, b, c, d; scanf("%d", &n); for (int i = 1; i <= n; i++) { scanf("%lf%lf%lf%lf", &a, &b, &c, &d); m = (a * c) / (b * d); printf("%.6lf\n", m); } return 0;
}
评论:
请先登录,才能进行评论