信鑫 • 26天前
using namespace std;
int main() {
int a = 100000;
int n;
cin >> n;
long long ans = 1;
if (n % 2 == 0) {
if (n >= 50) {
cout << 0 << endl;
}
for (int i = n; i >= 2; i -= 2)
ans = (ans * i) % a;
} else {
for (int i = n; i >= 1; i -= 2)
ans = (ans * i) % a;
}
cout << ans << endl;
return 0;
}
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