小唐唐 • 1个月前
using namespace std; typedef long long ll; const ll mod = 99999999;
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
ll n; cin >> n;
if (n == 1) { cout << "2\n3\n"; return 0; }
if (n == 2) { cout << "1\n4\n"; return 0; }
if (n == 3) { cout << "6\n5\n"; return 0; }
// 滚动数组，保存 f(i-2), f(i-1) 两行共四个值
ll f11 = 2, f12 = 3; // i=1
ll f21 = 1, f22 = 4; // i=2
ll f31 = 6, f32 = 5; // i=3
for (ll i = 4; i <= n; ++i) {
ll next1 = (f22 + 2 * f11 + 5) % mod;
ll next2 = (f21 + 3 * f11 + 2 * f12 + 3) % mod;
// 滚动更新
f11 = f21; f12 = f22;
f21 = f31; f22 = f32;
f31 = next1; f32 = next2;
}
cout << f31 << '\n' << f32 << '\n';
return 0;
}
评论:
#include <bits/stdc++.h>
using namespace std;
int main() {
int s=0;
int n;
cin>>n;
int h[4];
int v;
for(int i=1; i<=n; i++) {
cin>>v;
h[v%3]++;
}
s=h[0]/2+min(h[1],h[2]);
cout<<s<<endl;
return 0;
}
请先登录，才能进行评论