阮 • 12天前
using namespace std; int a[105], b[20005];
int main() {
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> a[i];
b [a[i]] = 1;
}
int ans = 0;
for (int i = 1; i <= n; i++) {
for (int j = i + 1; j <= n; j++) {
if (b[a[i] + a[j]] == 1 ) {
ans++;
b[a[i] + a[j]] = 0;
}
}
}
cout << ans;
return 0;
}
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