周睿 • 1天前
using namespace std;
int main() {
int a[100005];
int n, k = 1, h = 0;
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> a[i];
h = a[1];
}
for (int i = 1; i <= n; i++) {
if (h < a[i]) {
k++;
h = a[i];
}
}
cout << k;
return 0;
}
评论:
请先登录,才能进行评论