lkyLKY(祝忘羡99版) • 8天前
using namespace std;
int main() {
int n;
cin >> n;
int a[n][3];
for (int i = 0; i < n; i++) {
for (int j = 0; j < 3; j++) {
cin >> a[i][j];
}
}
int num = 0;
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
int sum1 = 0, sum2 = 0, count = 0;
for (int k = 0; k < 3; k++) {
sum1 += a[i][k];
sum2 += a[j][k];
if (abs(a[i][k] - a[j][k]) <= 5) {
count++;
}
}
if (count == 3 && abs(sum1 - sum2) <= 10) {
num++;
}
}
}
cout << num;
return 0;
}
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