lkyLKY(祝忘羡99版) • 11天前
using namespace std; const int N = 55; int a[N << 1][N];
int main() {
int n, m;
cin >> n >> m;
for (int i = 1; i <= n << 1; i++) {
for (int j = 1; j <= m; j++) {
cin >> a[i][j];
}
}
int ans = 0;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
if (a[i][j] == a[i + n][j])
ans++;
}
}
cout << ans;
return 0;
}
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