许诺 • 10天前
#include <iostream>
#include <vector>
#include <deque>
using namespace std;
int main() {
int n, m;
cin >> n >> m;
vector<int> cost(n + 1);
for (int i = 1; i <= n; ++i) {
cin >> cost[i];
}
vector<int> dp(n + 2, 0);
deque<int> q;
q.push_back(0);
dp[0] = 0;
for (int i = 1; i <= n + 1; ++i) {
while (!q.empty() && q.front() < i - m) {
q.pop_front();
}
dp[i] = dp[q.front()] + (i <= n ? cost[i] : 0);
while (!q.empty() && dp[i] <= dp[q.back()]) {
q.pop_back();
}
q.push_back(i);
}
cout << dp[n + 1] << endl;
return 0;
}
评论:
请先登录,才能进行评论