法2

int main() {

int n, c = 0, ans = 0;
scanf("%d", &n);
while (n > 0) {
	c++;
	if (n % 3 == 1 && ans == 0) {
		ans = c;

	}
	int s = n * 1.0 / 3 + 0.99999;
	n = n - s;

}
printf("%d %d", c, ans);

}