王峻谦 • 1个月前
using namespace std;
int main() {
int a[110][110];
int n, m, b = 0;
cin >> n >> m;
for (int c = 1; c <= n * 2; c++) {
for (int d = 1; d <= m; d++) {
cin >> a[c][d];
}
}
for (int c = 1; c <= n; c++) {
for (int d = 1; d <= m; d++) {
if (a[c][d] == a[c + n][d]) {
b++;
}
}
}
printf("%d", b);
return 0;
}
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