天下为公 · 发布于 2023-12-30 · 浏览 572 回复 0

return x<y;

int num[10000], n,k;
scanf("%d %d", &n,&k);
for (int i = 0; i < n; i++) {
	scanf("%d", &num[i]);
}
sort(num,num+n,cmp);
cout<<num[k-1];
return 0;