许熠谦 • 2年前
using namespace std; int main() {
int d,y,c=0,l=0;
for(int i=1;i<=12;i++)
{
cin>>d;
y=l+300-d;
c=c+y/100;
l=y%100;
if(y<0)
{
cout<<-i;
return 0;
}
}
cout<<c*100*1.2+l<<endl;
return 0;
}
评论:
using namespace std;
int main() {
int n, a, b, k, min = 99999999;
cin >> n;
for (int i = 1; i <= 3; i++) {
cin >> a >> b;
for (int j = 1;; j++)
if (a * j >= n) {
k = j * b;
break;
} else
continue;
if (k <= min)
min = k;
}
cout << min << endl;
return 0;
}
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