@黄裕坤 我不信你不会

include<stdio.h>

int main() {

int a[100000],n,i,j,k=0,t,x,c=1,y;
scanf("%d",&n);
for(i=0;i<n;i++)
{
    scanf("%d",&a[i]);
}
for (int j = 1; j <= n - 1; j++) {

for (int i = 0; i <= n - 1 - j; i++) {
	if (a[i] >= a[i + 1]) {
		x = a[i];
		y = a[i + 1];
		a[i] = y;
		a[i + 1] = x;
	}
}

}

for(i=0;i<n-1;i++)
{
    t=a[i];
    for(j=i+1;j<n;j++)
    {
        if(t==a[j])
        {
            c++;
        }
    }
    printf("%d %d\n",t,c);
}
return 0;

}

输入 12 9 1400000000 3 89 5645897 6 897456322 8 8 1500000000 90 89 输出 3 1 6 1 8 2 8 2 9 2 89 3 89 3 90 3 5645897 3 897456322 3 1400000000 3 答案 3 1 6 1 8 2 9 1 89 2 90 1 5645897 1 897456322 1 1400000000 1 1500000000 1 系统信息 exit code: 0, checker exit code: 0

emmm，我这题也过不去

试点卡的不错